document.write( "Question 726913: Find three consecutive odd integers that the product of the least and greatest is 16 more that the middle integer \n" ); document.write( "

Algebra.Com's Answer #444891 by fcabanski(1391) $\"\"$ $\"About$

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Call the integers x, x+2 and x+4 (the difference between consecutive odd integers is always 2.)

\n" ); document.write( "x is the least, and x+4 is the greatest, and their product is x(x+4) = $\"x%5E2+%2B+4x\"$

\n" ); document.write( "That product is 16 more than the middle integer, x+2 or it = x+2+16

\n" ); document.write( " $\"x%5E2+%2B+4x+=+x%2B18\"$

\n" ); document.write( " $\"x%5E2+%2B+3x+-18+=0\"$

\n" ); document.write( "(x+6)(x-3) = 0 so x=-6 and x=3

\n" ); document.write( "-6 is even, so x=3 and the integers are 3, 5, and 7

Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.) \n" ); document.write( "

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