document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726833>Question 726833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've been trying to set up system of equations and constraint inequalities for this problem, but it's been very difficult for me; help would be great. \r<BR>\n" );
document.write( "\n" );
document.write( "Premium gas sells at 62 cents/L. Regular gas sells at 59.5 cents/L. To boost sales, a middle octane gas is formed by mixing premium and regular. If 1000 L of this middle octane gas is produced and sold at 60.5 cents/L, how much of each type of gasoline was used?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444871 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Premium gas sells at 62 cents/L.<BR>\n" );
document.write( " Regular gas sells at 59.5 cents/L.<BR>\n" );
document.write( " To boost sales, a middle octane gas is formed by mixing premium and regular.<BR>\n" );
document.write( " If 1000 L of this middle octane gas is produced and sold at 60.5 cents/L, how much of each type of gasoline was used? <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let x = amt of 62 cent gas used<BR>\n" );
document.write( "the total is to be 1000L, therefore<BR>\n" );
document.write( "(1000-x) = amt of 59.5 cent gas<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A typical mixture equation<BR>\n" );
document.write( "62x + 59.5(1000-x) = 60.5(1000)<BR>\n" );
document.write( "62x + 59500 - 59.5x = 60500<BR>\n" );
document.write( "62x - 59.5x = 60500 - 59500<BR>\n" );
document.write( "2.5x = 1000<BR>\n" );
document.write( "x = 1000/2.5<BR>\n" );
document.write( "x = 400L of the 62 cent gas<BR>\n" );
document.write( "then<BR>\n" );
document.write( "1000-400 = 600L of the 59.5 cent gas<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check this<BR>\n" );
document.write( "62(400) + 59.5(600) = 60.5(1000)<BR>\n" );
document.write( "24800 + 35.700 = 60500  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );