document.write( "Question 63770: find the intrest rate using a=p(1+r)^t $2560 grows to $4840.00 in 2 years \n" ); document.write( "

Algebra.Com's Answer #44486 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"a+=+p%281%2Br%29%5Et\"$
\n" ); document.write( "p = 2560
\n" ); document.write( "a = 4840
\n" ); document.write( "t = 2
\n" ); document.write( " $\"4840+=+2560%281%2Br%29%5E2\"$
\n" ); document.write( " $\"log%284840%29+=+log%282560%29+%2B+2%2Alog%281+%2B+r%29\"$
\n" ); document.write( " $\"3.685+=+3.408+%2B+2%2Alog%281+%2B+r%29\"$
\n" ); document.write( " $\"2%2Alog%281+%2B+r%29+=+.277\"$
\n" ); document.write( " $\"log%281+%2B+r%29+=+.138\"$
\n" ); document.write( " $\"1+%2B+r+=+10%5E.138\"$
\n" ); document.write( " $\"1+%2B+r+=+1.375\"$
\n" ); document.write( " $\"r+=+.375\"$
\n" ); document.write( "The rate is 37.5 %
\n" ); document.write( "check
\n" ); document.write( " $\"4840+=+2560%281%2Br%29%5E2\"$
\n" ); document.write( " $\"4840+=+2560%281%2B.375%29%5E2\"$
\n" ); document.write( " $\"4840+=+2560%2A1.890\"$
\n" ); document.write( " $\"4840+=+4838\"$ pretty close, I rounded off calculations \n" ); document.write( "

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