document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726758>Question 726758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "the perimeter of a triangle is 480 meters. the second side is three times the first and the third side is sixty meters more than the second. what are the lengths of each side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444826 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=A+B+C<BR>\n" );
document.write( "B=3A<BR>\n" );
document.write( "C=B+60 OR C=3A+60<BR>\n" );
document.write( "480=A+3A+3A+60<BR>\n" );
document.write( "480=7A+60<BR>\n" );
document.write( "7A=480-60<BR>\n" );
document.write( "7A=420<BR>\n" );
document.write( "A=420/7<BR>\n" );
document.write( "A=60 ANS.<BR>\n" );
document.write( "B=3*60=180 ANS.<BR>\n" );
document.write( "C=3*60+60=180+60=240 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60+180+240=480<BR>\n" );
document.write( "480=480 </SPAN>\n" );
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