document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726752>Question 726752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sweetwater & Associates write weekend trip insurance at a very nominal charge. Records show that the probability that a motorist will have an accident during the weekend and file a claim is 0.05. Suppose they wrote 15 policies for the coming weekend, what is the probability that exactly two claims will be filed?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444796 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a binomial distribution problem.\r<BR>\n" );
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document.write( "In this case, n = 15, p = 0.05 and k = 2\r<BR>\n" );
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document.write( "So plug all of that into the formula below and evaluate.\r<BR>\n" );
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document.write( "P(X = k) = (n C r)*(p)^(k)*(1-p)^(n-k)\r<BR>\n" );
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document.write( "P(X = 2) = (15 C 2)*(0.05)^(2)*(0.95)^(15-2)\r<BR>\n" );
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document.write( "P(X = 2) = (105)*(0.05)^(2)*(0.95)^13\r<BR>\n" );
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document.write( "P(X = 2) = (105)*(0.0025)*(0.5133420832795)\r<BR>\n" );
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document.write( "P(X = 2) = 0.13475229686087\r<BR>\n" );
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document.write( "P(X = 2) = 0.134752\r<BR>\n" );
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document.write( "Final Answer (Rounded to 6 decimal places):\r<BR>\n" );
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document.write( "P(X = 2) = <font color=\"red\">0.134752</font> </SPAN>\n" );
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