document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726764>Question 726764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x^2+30x+52 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444777 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor<BR>\n" );
document.write( "(1) 2x^2 +30x + 52 = 0<BR>\n" );
document.write( "Always look for a common factor of ALL terms in the equation, then remove it to make the coefficients smaller and easier to work with. In (1), 2 is a common factor. Remove it leaves us with<BR>\n" );
document.write( "(2) x^2 + 15x + 26 = 0, which readily factors into<BR>\n" );
document.write( "(3) (x + 13)*(x + 2) = 0, which gives the roots <BR>\n" );
document.write( "(4) x = {-13,-2}<BR>\n" );
document.write( "Let's check these value using (1).<BR>\n" );
document.write( "Is (2*(-13)^2 +30*(-13) + 52 = 0)?<BR>\n" );
document.write( "Is (2*(169) -390 + 52 = 0)?<BR>\n" );
document.write( "Is (338 -390 + 52 = 0)?<BR>\n" );
document.write( "Is (-52 + 52 = 0)?<BR>\n" );
document.write( "Is (0 = 0)? Yes<BR>\n" );
document.write( "Is (2*(-2)^2 +30*(-2) + 52 = 0)?<BR>\n" );
document.write( "Is (2*4 -60 + 52 = 0)?<BR>\n" );
document.write( "Is (8 -60 + 52 = 0)?<BR>\n" );
document.write( "Is (-52 + 52 = 0)?<BR>\n" );
document.write( "Is (0 = 0)? Yes<BR>\n" );
document.write( "Answer: The solution for x = {-13,-2} </SPAN>\n" );
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