document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726749>Question 726749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of one side of a square is tripled and the length of an adjacent side is increased by 10, the resulting rectangle has an area that is 6 times the area of the original square. Find the length of a side of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444773 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s = the length of the side of the square.<BR>\n" );
document.write( "Then the rectangle is 3*s by s+10 giving the area<BR>\n" );
document.write( "(1) (3s)*(s+10) = 6s^2 or<BR>\n" );
document.write( "(2) 3s^2 + 30s = 6s^2 or<BR>\n" );
document.write( "(3) 3s^2 - 30s = 0 or<BR>\n" );
document.write( "(4) 3s*(s - 10) = 0 which has two solutions<BR>\n" );
document.write( "(5) s = 0,10<BR>\n" );
document.write( "Obviously we choose<BR>\n" );
document.write( "(6) s = 10<BR>\n" );
document.write( "Let's check this.<BR>\n" );
document.write( "Is (3*10*(10+10) = 6*10^2)?<BR>\n" );
document.write( "Is (30*20 = 6*100)?<BR>\n" );
document.write( "Is (600 = 600)? Yes<BR>\n" );
document.write( "Answer: The length of the side of the original square is 10 units. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );