document.write( "Question 726726: Solving log₂ 128=x \n" ); document.write( "

Algebra.Com's Answer #444769 by Alan3354(69443) $\"\"$ $\"About$

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$\"log%282%2C128%29+=+x\"$
\n" ); document.write( "--> $\"2%5Ex+=+128\"$
\n" ); document.write( "x = 7
\n" ); document.write( "===========
\n" ); document.write( "If you don't recognize that 128 = 2^7, then
\n" ); document.write( " $\"x+=+log%282%2C128%29\"$
\n" ); document.write( "x = log(128)/log(2)
\n" ); document.write( "x = 7
\n" ); document.write( " \n" ); document.write( "

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