document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726630>Question 726630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "four times a first number decreased by a second number is -38. The first number increased by four times the second number is 16. Find all numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444760 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4X-Y=-38 MULTIPLY BY 4 & ADD<BR>\n" );
document.write( "X+4Y=16<BR>\n" );
document.write( "16X-4Y=-152<BR>\n" );
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document.write( "17X=-136<BR>\n" );
document.write( "X=-136/17<BR>\n" );
document.write( "X=-8 ANS.<BR>\n" );
document.write( "4*-8-Y=-38<BR>\n" );
document.write( "-32-Y=-38<BR>\n" );
document.write( "-Y=-38+32<BR>\n" );
document.write( "-Y=-6<BR>\n" );
document.write( "Y=6 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "-8+4*6=16<BR>\n" );
document.write( "-8+24=16<BR>\n" );
document.write( "176=16 </SPAN>\n" );
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