document.write( "Question 726720: solve simalteneously for x and y:
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document.write( "x-y=3
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document.write( "2x^2-3xy+2y(y+1)=3x+13
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Algebra.Com's Answer #444754 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2x^2-3xy+2y(y+1)=3x+13 \n" ); document.write( "x-y=3 --> y = x-3 \n" ); document.write( "Sub for y in the 1st eqn' \n" ); document.write( "--------- \n" ); document.write( "2x^2-3x(x-3) +2(x-3)*(x-2) = 3x+13 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "===================== \n" ); document.write( "x = sqrt(5) + 2, y = sqrt(5) - 1 \n" ); document.write( "x =~ 4.236, y = 1.236 \n" ); document.write( "------------------------ \n" ); document.write( "x = 2 - sqrt(5), y = -1 - sqrt(5) \n" ); document.write( "x =~ -0.236, y = -3.236 \n" ); document.write( " \n" ); document.write( " |