document.write( "Question 726650: Solve the problem.\r
\n" ); document.write( "\n" ); document.write( "When interest is compounded continuously, the balance in an account after t years is given by P(t)= Poekt, where Po is the initial investment and k is the interest rate. Suppose that Po is invested in a savings account where interest is compunded continuously at 8% per year. Express P(t) in terms of Po and 0.08.\r
\n" ); document.write( "\n" ); document.write( "Possible answers are:\r
\n" ); document.write( "\n" ); document.write( "A) P(t)= Poo.08t
\n" ); document.write( "B) None
\n" ); document.write( "C) P(t)=Poe0.08t
\n" ); document.write( "D) P(t)=Poe8t
\n" ); document.write( "E) P(t)=Poe0.08
\n" ); document.write( "

Algebra.Com's Answer #444740 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"P%28t%29=+P%5B0%5De%5Ekt\" with
\n" ); document.write( "\"P%5B0%5D\"= amount originally invested (principal at time zero),
\n" ); document.write( "\"k\"= annual interest rate (expressed as a decimal), and
\n" ); document.write( "\"t\"= time in years,
\n" ); document.write( "gives the balance as a function of time.
\n" ); document.write( "
\n" ); document.write( "If the annual interest is 8%, the interest rate expressed as a decimal is
\n" ); document.write( "\"k=8%2F100\" --> \"k=0.08\" and
\n" ); document.write( "\"highlight%28P%28t%29=+P%5B0%5De%5E0.08t%29\"
\n" ); document.write( "
\n" ); document.write( "All you had to do is write \"0.08\" instead of \"k\" in the formula.
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