document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726649>Question 726649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help solve the below equations: <BR>\n" );
document.write( "Q1<BR>\n" );
document.write( "2950=2000(1+r)^10\r<BR>\n" );
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document.write( "Q2<BR>\n" );
document.write( "2p = p(1.09)^n\r<BR>\n" );
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document.write( "Thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444703 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q1: Given<BR>\n" );
document.write( "(1) 2950 = 2000*(1+r)^10 or<BR>\n" );
document.write( "(2) (1+r)^10 = 2950/2000 or<BR>\n" );
document.write( "(3) (1+r)^10 = 1.475<BR>\n" );
document.write( "Now take the 1/10th root of each side and get<BR>\n" );
document.write( "(4) 1+r = (1.475)^(0.1)<BR>\n" );
document.write( "Use your calculator to find<BR>\n" );
document.write( "(5) 1+r = 1.03963... or<BR>\n" );
document.write( "(6) r = 1.03963... -1 or<BR>\n" );
document.write( "(7) r = 0.03963... or<BR>\n" );
document.write( "(8) r = 100*(0.03963...) or<BR>\n" );
document.write( "(9) r = 3.963095.. %<BR>\n" );
document.write( "To check this value for r, put it into (1).<BR>\n" );
document.write( "Is (2950 = 2000*(1+0.0396...)^10)? <BR>\n" );
document.write( "Is (2950 = 2000*(1.0396...)^10)?<BR>\n" );
document.write( "Is (2950 = 2000*(1.475))?<BR>\n" );
document.write( "Is (2950 = 2950)? Yes<BR>\n" );
document.write( "Q1 Answer: r = 3.9631%<BR>\n" );
document.write( "Q2: Given<BR>\n" );
document.write( "(10) 2p = p*(1.09)^n or assuming p is not equal to zero we get<BR>\n" );
document.write( "(11) 2 = (1.09)^n<BR>\n" );
document.write( "Now take the ln (or LOG) of both sides of (11) to get<BR>\n" );
document.write( "(12) ln(2) = n*ln(1.09)<BR>\n" );
document.write( "Solve (12) for n to get<BR>\n" );
document.write( "(13) n = ln(2)/ln(1.09)<BR>\n" );
document.write( "Use your calculator to evaluate (13) to get<BR>\n" );
document.write( "(14) n = (0.693...)/(0.08617...) or<BR>\n" );
document.write( "(15) n = 8.04323...<BR>\n" );
document.write( "Check this value of n with (11)<BR>\n" );
document.write( "Is (2 = (1.09)^(8.04323...))?<BR>\n" );
document.write( "Is (2 = 2)? Yes<BR>\n" );
document.write( "Q2 Answer: n = 8.04323...\r<BR>\n" );
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