document.write( "Question 726631: complete the square
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document.write( "2m^2-m-15=0\r
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document.write( "using the quadratic formula
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document.write( "2y^2-3y-6=0 \n" );
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Algebra.Com's Answer #444702 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! complete the square \n" ); document.write( "2m^2-m-15=0 \n" ); document.write( "2(m^2-m/2+1/16)=15+1/8=120/8+1/8=121/8 \n" ); document.write( "2(m-1/4)^2=121/8 \n" ); document.write( "divide both sides by 2 \n" ); document.write( "(m-1/4)^2=121/16 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "m-1/4=±11/4 \n" ); document.write( "m=1/4±11/4 \n" ); document.write( "m=1/4+11/4=3 \n" ); document.write( "or \n" ); document.write( "m=1/4-11/4=-10/4=-5/2=-2.5 \n" ); document.write( ".. \n" ); document.write( "using the quadratic formula \n" ); document.write( "2y^2-3y-6=0 \n" ); document.write( "quadratic formula: \n" ); document.write( " \n" ); document.write( "a=2, b=-3, c=-6 \n" ); document.write( "y={-(-3)±√(-3)^2-4*2*-6)}/(2*2) \n" ); document.write( "=[3±√(9+48)]/4 \n" ); document.write( "=(3±√57)/4 \n" ); document.write( "y=(3+√57)/4 \n" ); document.write( "or \n" ); document.write( "y=(3-√57)/4 \n" ); document.write( " |