document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63773>Question 63773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to learn how to factor each polynomial completely, Can someone help me. Thanks\r<BR>\n" );
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document.write( "6m^2-19mn+10^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44470 by </B><A HREF=/tutors/aboutme.mpl?userid=tanimachatterjee><B>tanimachatterjee(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tanimachatterjee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> polynomial must be  6m^2 -19mn +10n^2\r<BR>\n" );
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document.write( "here we use middle term breaking \r<BR>\n" );
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document.write( "first multiply coefficient of m^2 & n^2<BR>\n" );
document.write( " here it is +60<BR>\n" );
document.write( " if it is positive then just break 60 in two factors so that sum of two is 19<BR>\n" );
document.write( " here 60 = 15*4<BR>\n" );
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document.write( "  6m^2 -19 mn + 10n^2\r<BR>\n" );
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document.write( "= 6m^2 -(15+4)mn +10 n^2\r<BR>\n" );
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document.write( "= 6m^2 -15mn -4mn + 10n^2\r<BR>\n" );
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document.write( "= 3m(2m - 5n) -2n(2m - 5n)\r<BR>\n" );
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document.write( "=(2m-5n)(3m-2n)<BR>\n" );
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