document.write( "Question 726623: The current of a stream moves at a speed of 5km/hr. A boat travels 31 km upstream back in 11 hours. What is the speed of the boat in still water? Round your answer to two decimal places.\r
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Algebra.Com's Answer #444691 by mananth(16946)![]() ![]() You can put this solution on YOUR website! I presume 31 km is up and down each way\r \n" ); document.write( "\n" ); document.write( "boat speed x kph \n" ); document.write( "current speed 5 kph \n" ); document.write( " \n" ); document.write( "against current x- 5 kph \n" ); document.write( "with current x+ 5 kph \n" ); document.write( " \n" ); document.write( "Distance= 31 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 11 hours \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "31 /( x + 5 ) + 31 /(x - 5 ) = 11 \n" ); document.write( " \n" ); document.write( "LCD = (x - 5 ) ( x + 5 ) \n" ); document.write( "31 *( x - 5 ) + 31 (x + 5 ) = 11 (x^2 - 25 ) \n" ); document.write( "31 x - -155 + 31 x + 155 = 11 ( x ^2 - 25 ) \n" ); document.write( "62 x = 11 x ^2 -275 \n" ); document.write( "11 x ^2 - -62 x - 275 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 11 , b= -62 , c= -275 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 3844 + 12100 \n" ); document.write( "b^2-4ac= 15944 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 62 + 126.27 )/ 22 \n" ); document.write( "x1= 8.56 \n" ); document.write( " \n" ); document.write( "x2=( 62 -126.27 ) / 22 \n" ); document.write( "x2= -2.92 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 8.56 kph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |