document.write( "Question 726623: The current of a stream moves at a speed of 5km/hr. A boat travels 31 km upstream back in 11 hours. What is the speed of the boat in still water? Round your answer to two decimal places.\r
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Algebra.Com's Answer #444691 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
I presume 31 km is up and down each way\r
\n" ); document.write( "\n" ); document.write( "boat speed x kph
\n" ); document.write( "current speed 5 kph
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\n" ); document.write( "against current x- 5 kph
\n" ); document.write( "with current x+ 5 kph
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\n" ); document.write( "Distance= 31 miles
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\n" ); document.write( "Time against + time with = 11 hours
\n" ); document.write( "t=d/r
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\n" ); document.write( "31 /( x + 5 ) + 31 /(x - 5 ) = 11
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\n" ); document.write( "LCD = (x - 5 ) ( x + 5 )
\n" ); document.write( "31 *( x - 5 ) + 31 (x + 5 ) = 11 (x^2 - 25 )
\n" ); document.write( "31 x - -155 + 31 x + 155 = 11 ( x ^2 - 25 )
\n" ); document.write( "62 x = 11 x ^2 -275
\n" ); document.write( "11 x ^2 - -62 x - 275
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\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 11 , b= -62 , c= -275
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\n" ); document.write( "b^2-4ac= 3844 + 12100
\n" ); document.write( "b^2-4ac= 15944
\n" ); document.write( "\"%09sqrt%28%0915944%09%29=%09126.27%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\" 0
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 62 + 126.27 )/ 22
\n" ); document.write( "x1= 8.56
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( 62 -126.27 ) / 22
\n" ); document.write( "x2= -2.92
\n" ); document.write( "Ignore negative value
\n" ); document.write( "boat speed 8.56 kph
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\n" ); document.write( "m.ananth@hotmail.ca
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