document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726620>Question 726620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the circumference of a circle is 24, and the angle measure of an arc is 120o, which is the length of the arc? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444678 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the circumference of a circle is 24, and the angle measure of an arc is 120o, which is the length of the arc?<BR>\n" );
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document.write( "Using radian meansure<BR>\n" );
document.write( "theta = (arc length)/radius<BR>\n" );
document.write( "---<BR>\n" );
document.write( "arc length = radius*theta<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "120 degrees = 120(pi/180) = (2/3)pi radians<BR>\n" );
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document.write( "circumference = 2pi*r<BR>\n" );
document.write( "24 = 2pi*r<BR>\n" );
document.write( "r = 12/pi<BR>\n" );
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document.write( "arc length = (12/pi)(2/3)pi = 8 units<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================== </SPAN>\n" );
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