document.write( "Question 63783: (4/y)-5=5/2y\r
\n" ); document.write( "\n" ); document.write( "Solve for y. \n" ); document.write( "
Algebra.Com's Answer #44467 by checkley71(8403)\"\" \"About 
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4/Y-5=(5/2)Y
\n" ); document.write( "4/Y-5Y/2=5
\n" ); document.write( "(8-5Y^2)/2Y=5
\n" ); document.write( "8-5Y^2=10Y
\n" ); document.write( "-5Y^2-10Y+8=0
\n" ); document.write( "5Y^2+10Y-8=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET
\n" ); document.write( "X=(-B+-SQRT[B^2-4AC])/2A
\n" ); document.write( "X=(-10+-SQRT[100-4*5*-8])/2*5
\n" ); document.write( "X=(-10+-SQRT[100+160)/10
\n" ); document.write( "X=(-10+-SQRT260)/10
\n" ); document.write( "X=(-10+-16.12)/10
\n" ); document.write( "x=(-10+16.12)/10
\n" ); document.write( "x=6.12/10
\n" ); document.write( "x=.612 solution.
\n" ); document.write( "x=(-10-16.12)/10
\n" ); document.write( "x=-26.12/10
\n" ); document.write( "x=-2.612 solution. \n" ); document.write( "
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