document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726614>Question 726614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the width of a rectangle is 5 meters less than the length and the perimeter of the rectangle is 53 meters, find the length and width. could you show me how to do this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444661 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If the width of a rectangle is 5 meters less than the length and the perimeter of the rectangle is 53 meters, find the length and width.<BR>\n" );
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document.write( "Let length be \"x\".<BR>\n" );
document.write( "Then width is \"x-5\"<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Perimeter = 2(length + width)<BR>\n" );
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document.write( "53 = 2(x + x-5)<BR>\n" );
document.write( "53 = 2(2x-5)<BR>\n" );
document.write( "53 = 4x-10<BR>\n" );
document.write( "4x = 63<BR>\n" );
document.write( "x = 15.75 meters (length)<BR>\n" );
document.write( "x-5 = 10.75 meters (width)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
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