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document.write( " (d) How much 70% alcohol solution must be mixed with a 30% alcohol solution to produce 60 liters of a 40% alcohol solution?\r
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Algebra.Com's Answer #444639 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .70x+.30(60-x)=.40*60 \n" ); document.write( ".70x+18-.30x=24 \n" ); document.write( ".40x=24-18 \n" ); document.write( ".40x=6 \n" ); document.write( "x=6/.40 \n" ); document.write( "x=15 liters of 70% solution is used. \n" ); document.write( "60-15=45 liters of 30% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".70*15+.30*45=.40*60 \n" ); document.write( "10.5+13.5=24 \n" ); document.write( "24=24 \n" ); document.write( " \n" ); document.write( " |