document.write( "Question 726509: \r
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\n" ); document.write( "\n" ); document.write( " (d) How much 70% alcohol solution must be mixed with a 30% alcohol solution to produce 60 liters of a 40% alcohol solution?\r
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Algebra.Com's Answer #444639 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.70x+.30(60-x)=.40*60
\n" ); document.write( ".70x+18-.30x=24
\n" ); document.write( ".40x=24-18
\n" ); document.write( ".40x=6
\n" ); document.write( "x=6/.40
\n" ); document.write( "x=15 liters of 70% solution is used.
\n" ); document.write( "60-15=45 liters of 30% solution is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".70*15+.30*45=.40*60
\n" ); document.write( "10.5+13.5=24
\n" ); document.write( "24=24
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