document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726565>Question 726565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the inequalities:\r<BR>\n" );
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document.write( "5x-6+3x<2+9x-5?<BR>\n" );
document.write( "This is what I did..<BR>\n" );
document.write( "5x+3x=8X-6<-3+9x.......because 2-(-5)=-3<BR>\n" );
document.write( "then I cancelled the 6 on one side and -3+6=3<BR>\n" );
document.write( "then I 8x<3+9x now what do I do? Do I divide it by 9it would be x<3 it doesn't make sense. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444630 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-6+3x<2+9x-5<BR>\n" );
document.write( "8x-6<-3+9x<BR>\n" );
document.write( "8x-9x<-3+6<BR>\n" );
document.write( "-x<3 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "Let x=-2.9<BR>\n" );
document.write( "5(-2.9)-6+3(-2.9)<2+9(-2.9)-5<BR>\n" );
document.write( "-14.5-6-8.7<2-26.1-5<BR>\n" );
document.write( "-29.2<2-31.1<BR>\n" );
document.write( "-29.2<-29.1 </SPAN>\n" );
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