document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726431>Question 726431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the old days a pony express, traveling at the rate of 60 miles a day, had been gone 5 days, when a second pony express was sent after them, travelling at the rate of 75 miles per day. In what time would the one overtake the other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444612 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = rate x time<P><BR>\n" );
document.write( "The first rider traveled 60*5 = 300 miles.<P><BR>\n" );
document.write( "The second rider overtakes the first at 75-60 = 15 miles per day and must make up that 300 miles.<P><BR>\n" );
document.write( "300 = 15 * t <P><BR>\n" );
document.write( "300/15 = t = 20 days.<BR>\n" );
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