document.write( "Question 726429: If one number exceeds another number by 3 and the square of the larger exceeds the square of the smaller by 99, what are the numbers? \n" ); document.write( "

Algebra.Com's Answer #444610 by fcabanski(1391) $\"\"$ $\"About$

You can put this solution on YOUR website!
Call the numbers x and y.

\n" ); document.write( "Condition 1: x=y+3. Condition 2: $\"x%5E2+=+y%5E2+%2B+99\"$

\n" ); document.write( "Substitute x=y+3 into the second equation: $\"%28y%2B3%29%5E2+=+y%5E2+%2B+99\"$

\n" ); document.write( " $\"y%5E2+%2B6y+%2B+9+=+y%5E2+%2B99\"$ ---> (subtract y squared from both sides and subtract 9 from both sides): 6y = 90 ---> y = 15.

\n" ); document.write( "x = 15+ 3 = 18
\n" ); document.write( "

Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.) \n" ); document.write( "

\n" );