document.write( "Question 726475: 21<6u
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Algebra.Com's Answer #444602 by lenny460(1073)\"\" \"About 
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21<6u\r
\n" ); document.write( "\n" ); document.write( "21 < 6u\r
\n" ); document.write( "\n" ); document.write( "Divide each side of the inequality by 3.\r
\n" ); document.write( "\n" ); document.write( "21/3 = 7\r
\n" ); document.write( "\n" ); document.write( "6u/3 = 2u\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
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\n" ); document.write( "\n" ); document.write( "7 < 2u or\r
\n" ); document.write( "\n" ); document.write( "2u > 7
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