document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726412>Question 726412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If we increase two opposite sides of a square by 4 feet and the other two opposite sides by 6 feet, we shall then have a rectangle whose area is 74 square feet more than the square. Find a side of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444592 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side of square=x<BR>\n" );
document.write( "area = x^2\r<BR>\n" );
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document.write( "length of rectangle = x+6<BR>\n" );
document.write( "width of rectangle = (x+4)<BR>\n" );
document.write( "Area = (x+4)(x+6)\r<BR>\n" );
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document.write( "(x+4)(x+6)-x^2=74\r<BR>\n" );
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document.write( "x^2+10x+24-x^2=74\r<BR>\n" );
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document.write( "10x=50\r<BR>\n" );
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document.write( "x=5\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );