document.write( "Question 726075: The foci and ellipse : (x-3)^2/36+(y+2)^2/25=1 \n" ); document.write( "

Algebra.Com's Answer #444577 by lwsshak3(11628) $\"\"$ $\"About$

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The foci and ellipse :
\n" ); document.write( "(x-3)^2/36+(y+2)^2/25=1
\n" ); document.write( "This is an equation of an ellipse with horizontal major axis.
\n" ); document.write( "Its standard form: $\"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\"$ , a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given equation:
\n" ); document.write( "center:(3,-2)
\n" ); document.write( "a^2=36
\n" ); document.write( "b^2=25
\n" ); document.write( "c^2=a^2-b^2=36-25=11
\n" ); document.write( "c=√11≈3.3 (center to foci)
\n" ); document.write( "foci: (3ąc,-2)=(3ą3.3,-2)=(-.3,-2) and (6.3,-2) \n" ); document.write( "

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