document.write( "Question 63761: A store is selling CD's for $10.50 and for $8.50. You buy 10 total and spend $93.00. How many of each price did you buy? \n" ); document.write( "
Algebra.Com's Answer #44456 by Earlsdon(6294)\"\" \"About 
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Let x = the number of CDs at $10.50 each, and y = the number of CDs at $8.50 each.
\n" ); document.write( "The total number of CDs is: x + y = 10 Rewrite this as: x = 10 - y and substitute in the equation below:
\n" ); document.write( "The total cost of CDs is: (x)($10.50) + y($8.50) = $93.00\r
\n" ); document.write( "\n" ); document.write( "(10 - y)(10.5) + y(8.5) = 93. Simplify and solve for y.
\n" ); document.write( "105 - (10.5)y + (8.5)y = 93 Subtract 105 from both sides.
\n" ); document.write( "-10.5y + 8.5y = - 12
\n" ); document.write( "-2y = -12 Divide both sides by -2.
\n" ); document.write( "y = 6
\n" ); document.write( "x = 10 - y
\n" ); document.write( "x = 10 - 6
\n" ); document.write( "x = 4\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "4($10.50) + 6($8.50) = $42.00 + $51.00 = $93.00
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