document.write( "Question 726305: find 3 consecutive odd numbers whose sum is 5 more than twice the next consecutive odd number
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Algebra.Com's Answer #444549 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If \"x\" is any \"odd\" number, then \"x\" and \"x+%2B+2\" are consecutive odd numbers.\r
\n" ); document.write( "\n" ); document.write( "you need four consecutive odd numbers, and they are:\"x\",\"x+%2B+2\", \"x+%2B+4\", and \"x+%2B+6\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"3\" consecutive odd numbers whose sum is \"5\" more than twice the next (fourth) consecutive odd number\r
\n" ); document.write( "\n" ); document.write( "so, you have\r
\n" ); document.write( "\n" ); document.write( "\"x%2B%28x+%2B+2%29%2B%28x+%2B+4%29=2%28x+%2B+6%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Bx+%2B+2%2Bx+%2B+4=2x+%2B+12%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+6=2x+%2B+17\"\r
\n" ); document.write( "\n" ); document.write( "\"3x-2x=17-6\"\r
\n" ); document.write( "\n" ); document.write( "\"x=11\"......first odd number\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2=13\".....second odd number\r
\n" ); document.write( "\n" ); document.write( "\"x%2B4=15\".....third odd number\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"x%2B6=17\".....fourth odd number\r
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