document.write( "Question 725393: Give (a) the domain and (b) the zeros of f.\r
\n" ); document.write( "\n" ); document.write( "f(x) = 3x^3 - x^2 - 2x / x(x+1)^2\r
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Algebra.Com's Answer #444532 by General_Lee87(58)\"\" \"About 
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The domain appears to be all values of x except x = -1 and x = 0
\n" ); document.write( " The range appears to be all values of y.
\n" ); document.write( " The zeroes (roots) appear to be x = -2/3 and x = 1. \r
\n" ); document.write( "\n" ); document.write( "you find the domain by looking for all values of x that will result in a value of y.
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\n" ); document.write( "all values of x will result in a value of y except when x = -1 and when x = 0. \r
\n" ); document.write( "\n" ); document.write( "when x = -1 or when x = 0, the denominator of the original equation will be equal to 0 which makes the value of y undefined.
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\n" ); document.write( "therefore x = -1 and x = 0 can't be in the domain. \r
\n" ); document.write( "\n" ); document.write( "since there are no further restrictions as to what the value of x can be, then the domain is all values of x except at x = -1 and x = 0.
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\n" ); document.write( "the zeroes of the equation are found by setting the equation equal to 0 and solving for x.
\n" ); document.write( " it's best to simplify the equation first. \r
\n" ); document.write( "\n" ); document.write( "start with (3x^3 - x^2 - 2x) / (x * (x+1)^2 \r
\n" ); document.write( "\n" ); document.write( "since (3x^3 - x^2 - 2x) / x is equal to (3x^2 - x - 2), the equation becomes: \r
\n" ); document.write( "\n" ); document.write( "(3x^2 - x - 2) / (x+1)^2 \r
\n" ); document.write( "\n" ); document.write( "set this equal to 0 to get: \r
\n" ); document.write( "\n" ); document.write( "(3x^2 - x - 2) / (x + 1)^2 = 0 \r
\n" ); document.write( "\n" ); document.write( "multiply both sides of the equation by (x + 1)^2 to get: \r
\n" ); document.write( "\n" ); document.write( "(3x^2 - x - 2) = 0 \r
\n" ); document.write( "\n" ); document.write( "factor to get: \r
\n" ); document.write( "\n" ); document.write( "(3x + 2) (x - 1) = 0 \r
\n" ); document.write( "\n" ); document.write( "solve for x to get: \r
\n" ); document.write( "\n" ); document.write( "x = -2/3 or x = 1 \r
\n" ); document.write( "\n" ); document.write( "these are the roots of the quadratic equation which is the point at which the equation crosses the x-axis which is the zeroes of the equation.
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\n" ); document.write( "you can confirm that the solutions are correct by graphing the equation. \r
\n" ); document.write( "\n" ); document.write( "from the graph, you can see that the zeroes of the graph are around x = -2/3 and x = 1.
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\n" ); document.write( "from the graph, you can see that there appears to be an asymptote at around x = -1 although it's not real easy to see that.
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\n" ); document.write( "from the graph, you cannot see that there is a hole at x = 0 \r
\n" ); document.write( "\n" ); document.write( "the value of y is undefined at x = -1 and also undefined at x = 0. \r
\n" ); document.write( "\n" ); document.write( "this is because the denominator of the equation is 0 at those values of x. \r
\n" ); document.write( "\n" ); document.write( "at x = -1, this results in an asymptote. \r
\n" ); document.write( "\n" ); document.write( "at x = 0, this results in a hole. \r
\n" ); document.write( "\n" ); document.write( "if you try to find the value of y when x = 0 and when x = -1, you will not be able to.
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\n" ); document.write( "you can find a value of y for any other value of x other than 0 or -1.
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