document.write( "Question 726217: evaluate and simplify in a+bi form (4+ i sqrt 3) + (2- 2i sqrt 3)
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Algebra.Com's Answer #444517 by jim_thompson5910(35256)\"\" \"About 
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(4+ i*sqrt(3)) + (2- 2i*sqrt(3))\r
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\n" ); document.write( "\n" ); document.write( "4+ i*sqrt(3) + 2- 2i*sqrt(3)\r
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\n" ); document.write( "\n" ); document.write( "(4+2)+ (i*sqrt(3)- 2i*sqrt(3))\r
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\n" ); document.write( "\n" ); document.write( "(4+2)+ (sqrt(3)- 2*sqrt(3))*i\r
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\n" ); document.write( "\n" ); document.write( "(6)+ (-1*sqrt(3))*i\r
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\n" ); document.write( "\n" ); document.write( "(6)+ (-sqrt(3))*i\r
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\n" ); document.write( "\n" ); document.write( "6 - sqrt(3)*i\r
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\n" ); document.write( "\n" ); document.write( "The answer is \"6+-+sqrt%283%29%2Ai\" or \"6-i%2Asqrt%283%29\" and it is in a+bi form where \"a=6\" and \"b+=+-sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: the i term is NOT in (or under) the square root
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