document.write( "Question 726152: Space Shuttle 2 takes off 0.5 hour after Shuttle 1 and overtakes Shuttle 1 exactly 5 hours after Shuttle 2 takes off, find\r
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document.write( "a)the speed of Shuttle 1 and
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document.write( "b)the distance from the launch pad when shuttle 2 overtakes Shuttle 1 \n" );
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Algebra.Com's Answer #444490 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "D=RT \n" ); document.write( "D=(R+300)5 SHUTTLE #2' \n" ); document.write( "D=R(5+.5) \n" ); document.write( "(R+300)5=R(5+.5) \n" ); document.write( "5R+1500=R*5.5 \n" ); document.write( "5R+1500=5.5R \n" ); document.write( "5R-5.5R=-1500 \n" ); document.write( ".5R=-1500 \n" ); document.write( "R=-1500/-.5 \n" ); document.write( "R=3000 MPH IS THE SPEED OF SHUTTLE #1. \n" ); document.write( "D=3300*5 \n" ); document.write( "3000+300=3300 MPH FOR THE SPEED OF SHUTTLE #2. \n" ); document.write( "D=16,500 MILE THEY WILL MEET. \n" ); document.write( "PROOF: \n" ); document.write( "16,500=3000*5.5 \n" ); document.write( "16,500=16,500 \n" ); document.write( " |