document.write( "Question 726152: Space Shuttle 2 takes off 0.5 hour after Shuttle 1 and overtakes Shuttle 1 exactly 5 hours after Shuttle 2 takes off, find\r
\n" ); document.write( "\n" ); document.write( "a)the speed of Shuttle 1 and
\n" ); document.write( "b)the distance from the launch pad when shuttle 2 overtakes Shuttle 1
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Algebra.Com's Answer #444490 by checkley79(3341)\"\" \"About 
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\n" ); document.write( "D=RT
\n" ); document.write( "D=(R+300)5 SHUTTLE #2'
\n" ); document.write( "D=R(5+.5)
\n" ); document.write( "(R+300)5=R(5+.5)
\n" ); document.write( "5R+1500=R*5.5
\n" ); document.write( "5R+1500=5.5R
\n" ); document.write( "5R-5.5R=-1500
\n" ); document.write( ".5R=-1500
\n" ); document.write( "R=-1500/-.5
\n" ); document.write( "R=3000 MPH IS THE SPEED OF SHUTTLE #1.
\n" ); document.write( "D=3300*5
\n" ); document.write( "3000+300=3300 MPH FOR THE SPEED OF SHUTTLE #2.
\n" ); document.write( "D=16,500 MILE THEY WILL MEET.
\n" ); document.write( "PROOF:
\n" ); document.write( "16,500=3000*5.5
\n" ); document.write( "16,500=16,500
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