document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63754>Question 63754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The greenhouse I am building for my wife is 6 feet longer than it is wide. Write an algebraic expression for the perimeter if the length is expressed as X. If X equals 20, what is the perimeter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44449 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The greenhouse I am building for my wife is 6 feet longer than it is wide. Write an algebraic expression for the perimeter if the length is expressed as X. If X equals 20, what is the perimeter?<BR>\n" );
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document.write( "length = x = 20<BR>\n" );
document.write( "width = x-6= 14<BR>\n" );
document.write( "Perimeter = 2*length + 2*width<BR>\n" );
document.write( "Perimeter = 2*20 + 2*14=40+28=68 feet<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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