document.write( "Question 726068: The line x+3y-2=0 bisects the angle between the pair of straight lines of which one has the equation x-7y+5=0. The equation of other line is,,? \n" ); document.write( "
Algebra.Com's Answer #444466 by Alan3354(69443)\"\" \"About 
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The line x+3y-2=0 bisects the angle between the pair of straight lines of which one has the equation x-7y+5=0. The equation of other line
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\n" ); document.write( "Find the point of intersection of the 2 lines and the slope of each line.
\n" ); document.write( "x+3y-2=0 slope = -1/3 (the bisector line)
\n" ); document.write( "x-7y+5=0 slope = 1/7
\n" ); document.write( "--> (-1/10,7/10) intersection
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\n" ); document.write( "The angle between the lines and the x-axis is the atan of the slope.
\n" ); document.write( "atan(-1/3) =~ -18.435 degs
\n" ); document.write( "atan(1/7) =~ 8.13 degs
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\n" ); document.write( "The angle between the 2 lines =~ 26.565 degs
\n" ); document.write( "The angle of the \"other line\" will be -26.565 -18.435 = -45 degs
\n" ); document.write( "Its slope = -1 and it passes thru (-1/0,7/10)
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\n" ); document.write( "--> y = -x + 6/10\r
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