document.write( "Question 63752: A metal alloy is 25% copper. Another metal alloy is 50% copper. How much of each alloy should be mixed to create 1000 grams of an alloy that is 45% copper? \n" ); document.write( "
Algebra.Com's Answer #44446 by stanbon(75887)\"\" \"About 
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A metal alloy is 25% copper. Another metal alloy is 50% copper. How much of each alloy should be mixed to create 1000 grams of an alloy that is 45% copper?
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\n" ); document.write( "Let amount of 25% alloy be \"x\" ; amount of copper in it is 0.25x grams
\n" ); document.write( "Amount of 50% alloy is \"1000-x\" ;
\n" ); document.write( "amount of copper is 0.5(1000-x)=500-0.5x grams
\n" ); document.write( "Amount of mixture is 1000 grams; amount of copper is .45(1000)=450 grams
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\n" ); document.write( "EQUATION:
\n" ); document.write( "copper + copper = copper
\n" ); document.write( "0.25x+500-0.5x=450
\n" ); document.write( "-0.25x=-50
\n" ); document.write( "x=200 grams (amount of 25% alloy)
\n" ); document.write( "1000-x=800 grams (amount of 50% alloy)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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