document.write( "Question 63752: A metal alloy is 25% copper. Another metal alloy is 50% copper. How much of each alloy should be mixed to create 1000 grams of an alloy that is 45% copper? \n" ); document.write( "
Algebra.Com's Answer #44446 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A metal alloy is 25% copper. Another metal alloy is 50% copper. How much of each alloy should be mixed to create 1000 grams of an alloy that is 45% copper? \n" ); document.write( "------------ \n" ); document.write( "Let amount of 25% alloy be \"x\" ; amount of copper in it is 0.25x grams \n" ); document.write( "Amount of 50% alloy is \"1000-x\" ; \n" ); document.write( "amount of copper is 0.5(1000-x)=500-0.5x grams \n" ); document.write( "Amount of mixture is 1000 grams; amount of copper is .45(1000)=450 grams \n" ); document.write( "----------- \n" ); document.write( "EQUATION: \n" ); document.write( "copper + copper = copper \n" ); document.write( "0.25x+500-0.5x=450 \n" ); document.write( "-0.25x=-50 \n" ); document.write( "x=200 grams (amount of 25% alloy) \n" ); document.write( "1000-x=800 grams (amount of 50% alloy) \n" ); document.write( "-------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |