document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8062>Question 8062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not figure this out>>>>  Thanks for your help<BR>\n" );
document.write( "Marta leaves home at 9 am bicycling at a rate of 24 mi/h two hours later John leaves driving at a rate of 48 mi/h at what time will john catch up with Marta </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4444 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 24 mph, Marta ought to consider competing in the Tour de France.\r<BR>\n" );
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document.write( "Using the formula: d = rt (distance = rate X time)\r<BR>\n" );
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document.write( "For Marta: d1 = (r1)(t1) = 24(t1)<BR>\n" );
document.write( "For John: d2 = (r2)(t2) = 48(t2)\r<BR>\n" );
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document.write( "But Marta's time is 2 hours longer than John's time, so t1 = t2+2.<BR>\n" );
document.write( "And when John catches up with Marta, they will both have traveled the same distance, so, d1 = d2\r<BR>\n" );
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document.write( "d2 = d1<BR>\n" );
document.write( "48(t2) = 24(t2+2)<BR>\n" );
document.write( "48t2 = 24t2 + 48<BR>\n" );
document.write( "24t2 = 48<BR>\n" );
document.write( "t2 = 2 and t1 = t2+2 = 4\r<BR>\n" );
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document.write( "Now Marta leaves at 9:00 am and takes 4 hours while John leaves at 11:00 am and takes 2 hours.\r<BR>\n" );
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document.write( "So they will meet up at 9:00 am + 4 hours = 1:00 pm or<BR>\n" );
document.write( "11:00 am + 2 hours = 1:00 pm.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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