document.write( "Question 725888: at a fast food restaurant, a family bought 4 hamburgers and 3 bags of french fries for $4.20. At the same time, a family traveling with them bought 5 hamburgers and 2 bags of french fries for $4.55. What was the cost of one hamburger and cost of 1 bag of fries \n" ); document.write( "
Algebra.Com's Answer #444378 by sfischer18(2)![]() ![]() ![]() You can put this solution on YOUR website! let x=cost of one hamburger \n" ); document.write( "let y=cost of one bag of fries \n" ); document.write( ".. \n" ); document.write( "4x+3y=4.20 \n" ); document.write( "5x+2y=4.55 \n" ); document.write( ".. \n" ); document.write( "8x+6y=8.40 \n" ); document.write( "15x+6y=13.65 \n" ); document.write( "subtract \n" ); document.write( "-7x=-5.25 \n" ); document.write( "x=.75 \n" ); document.write( ".. \n" ); document.write( "3y=4.20-4x \n" ); document.write( "3y=1.20 \n" ); document.write( "y=.40 \n" ); document.write( "cost of one hamburger=$.75 \n" ); document.write( "cost of one bag of fries=$.40 \n" ); document.write( " |