document.write( "Question 725883: A rectangle is 6cm longer than it is wide. If the length is increased by 2cm and the width is increased by 1cm, the area of the rectangle is increased by 56cm^2. Find the dimensions of the rectangle. ...Thank You!! \n" ); document.write( "
Algebra.Com's Answer #444369 by mananth(16946)\"\" \"About 
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width x
\n" ); document.write( "length = x+6\r
\n" ); document.write( "\n" ); document.write( "Area = x(x+6)\r
\n" ); document.write( "\n" ); document.write( "new width--------x+1
\n" ); document.write( "new length ------x+6+2\r
\n" ); document.write( "\n" ); document.write( "Area = (x+1)(x+8)\r
\n" ); document.write( "\n" ); document.write( "The difference between the areas is 56\r
\n" ); document.write( "\n" ); document.write( "(x+1)(x+8)-x(x+6) =56\r
\n" ); document.write( "\n" ); document.write( "x^2+9x+8-x^2-6x=56
\n" ); document.write( "3x+8=56
\n" ); document.write( "3x=48
\n" ); document.write( "x=16 \r
\n" ); document.write( "\n" ); document.write( "width = 16 cm
\n" ); document.write( "length = 22cm
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