document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=725800>Question 725800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you do this equation by adding or using substitution??\r<BR>\n" );
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document.write( "4x=-3y-54<BR>\n" );
document.write( "X=2y+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444321 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you do this equation by adding or using substitution??\r<BR>\n" );
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document.write( "4x=-3y-54<BR>\n" );
document.write( "X=2y+3<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Using substitution, sub for x in the 1st equation.<BR>\n" );
document.write( "x = 2y + 3<BR>\n" );
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