document.write( "Question 725775: Log1/3(x2+x)-log1/3(x2-x)=-1 \n" ); document.write( "

Algebra.Com's Answer #444303 by lwsshak3(11628) $\"\"$ $\"About$

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Log1/3(x2+x)-log1/3(x2-x)=-1
\n" ); document.write( "log1/3[(x^2+x)/(x^2-x)]=-1
\n" ); document.write( "convert to exponential form: base(1/3) raised to log of number(-1)=number((x^2+x)/(x^2-x)
\n" ); document.write( "(1/3)^-1=(x^2+x)/(x^2-x)
\n" ); document.write( "3=x(x+1)/x(x-1)
\n" ); document.write( "3x-3=x+1
\n" ); document.write( "2x=4x
\n" ); document.write( "x=2 \n" ); document.write( "

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