document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8065>Question 8065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4443 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number of milliliters of pure alcohol. \r<BR>\n" );
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document.write( "Then we have:<BR>\n" );
document.write( " 400(15%) + x(100%) = (400+x)(32%) Change the percents to decimals.\r<BR>\n" );
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document.write( "400(0.15) + x(1) = (400+x)(0.32)  Simplify and solve for x.\r<BR>\n" );
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document.write( "60 + x = 128 + 0.32x  Subtract 0.32x from both sides.<BR>\n" );
document.write( "60 + 0.68x = 128 Subtract 60 from both sides.<BR>\n" );
document.write( "0.68x = 68 Divide both sides by 0.68<BR>\n" );
document.write( "x = 100 ml of pure alcohol is required.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "400(0.15) + 100 = (400+100)(0.32)<BR>\n" );
document.write( "60 + 100 = 500(0.32)<BR>\n" );
document.write( "160 = 160 Check ok.<BR>\n" );
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