document.write( "Question 725734: One number is three less than another number. The sum of their squares is 117. What are the 2 numbers. \n" ); document.write( "
Algebra.Com's Answer #444292 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! Let x & x-3 be thw 2 numbers. \n" ); document.write( "x^2+(x-3)^2=117 \n" ); document.write( "x^2+x^2-6x+9=117 \n" ); document.write( "2x^2-6x+9-117=0 \n" ); document.write( "2x^2-6x-108=0 \n" ); document.write( "2(x^2-3x-54)=0 \n" ); document.write( "2(x-9)(x+6)=0 \n" ); document.write( "x-9=0 \n" ); document.write( "x=9 ans for the larger number. \n" ); document.write( "9-3=6 ans. for the smaller number. \n" ); document.write( "Proof: \n" ); document.write( "6^2+9^2=117 \n" ); document.write( "36+81=117 \n" ); document.write( "117=117 \n" ); document.write( " |