document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60452>Question 60452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a book is 80 square inches How many 1x1x1 centimeter trianles wwould it take to cover the book? Each side of the triangle is 1 centimeter and 2.54 centimeters equal one inch. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44429 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> EACH TRINGLE HAS AN AREA OF <BR>\n" );
document.write( "1/2B*H OR .5*1*H AND THE HEIGHT IS FOUND BY THE PATHAGORIAN THE0REM A^2+B^2=C^2.<BR>\n" );
document.write( "WE HAVE C=1 & B=.5 NOW WE SOLVE FOR A<BR>\n" );
document.write( "A^2+.5^2=1^2<BR>\n" );
document.write( "A^2+.25=1<BR>\n" );
document.write( "A^2=1-.25<BR>\n" );
document.write( "A^2=.75 NOW WE CALCULATE THE SQUARE ROOT OF BOTH SIDES & WE GET <BR>\n" );
document.write( "A=.866 FOR THE HEIGHT. NOW WE CAN CALCULATE THE AREA OF EACH TRIANGLE IN CMs.<BR>\n" );
document.write( "AREA=.5*1*.866<BR>\n" );
document.write( "AREA=.433 SQUARE CMs.<BR>\n" );
document.write( "NOW WE CAN CONVERT THE SIZE OF THW BOOK IN INCHES TO CM OR CONVERT THE TRIANGLE IN CMs TO INCHES. LETS CONVERT THE 80 SQ. INCHES TO CMs. <BR>\n" );
document.write( "80*2.54=203.2 SQ CMs.<BR>\n" );
document.write( "NOW WE DIVIDE THE BOOK AREA BY THE SIZE OF THE TRIANGLE THUS<BR>\n" );
document.write( "203.2/.433=469.284 TRIANGLES WOULD COVER THE BOOK.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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