document.write( "Question 724278: How do i find the focus of the problem (y+3)^2=x-2 \n" ); document.write( "

Algebra.Com's Answer #444220 by lwsshak3(11628) $\"\"$ $\"About$

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How do i find the focus of the problem (y+3)^2=x-2
\n" ); document.write( "This is an equation of a parabola that opens rightward.
\n" ); document.write( "Its basic form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (2,-3)
\n" ); document.write( "axis of symmetry: y=3
\n" ); document.write( "4p=1
\n" ); document.write( "p=1/4
\n" ); document.write( "focus: (9/4,-3) (p-distance to the right of the vertex on the axis of symmetry)
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