document.write( "Question 725557: Okay, been messing with the problem for quite some time. Please help with set up, I seem to be missing something key to the problem:\r
\n" ); document.write( "\n" ); document.write( "How old is Blanche today if the square of her age 3 years from now, minus 10 times her age 2 years ago is 50. I keep thinking it must be something like :\r
\n" ); document.write( "\n" ); document.write( "(x+3)^2 - 10x-2=50\r
\n" ); document.write( "\n" ); document.write( "But it is not working out.
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Algebra.Com's Answer #444208 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
the square of her age 3 years from now ---> (x+3)^2\r
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\n" ); document.write( "\n" ); document.write( "10 times her age 2 years ago ----> 10(x-2)\r
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\n" ); document.write( "\n" ); document.write( "\"How old is Blanche today if the square of her age 3 years from now, minus 10 times her age 2 years ago is 50\"\r
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\n" ); document.write( "\n" ); document.write( "turns into\r
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\n" ); document.write( "\n" ); document.write( "(x+3)^2 - 10(x - 2) = 50\r
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\n" ); document.write( "\n" ); document.write( "Solve for x\r
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\n" ); document.write( "\n" ); document.write( "(x+3)^2 - 10(x - 2) = 50\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 6x + 9 - 10(x - 2) = 50\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 6x + 9 - 10x + 20 = 50\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 6x + 9 - 10x + 20 - 50 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2-4x-21 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x-7)(x+3) = 0\r
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\n" ); document.write( "\n" ); document.write( "x-7 = 0 or x+3 = 0\r
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\n" ); document.write( "\n" ); document.write( "x = 7 or x = -3\r
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\n" ); document.write( "\n" ); document.write( "Ignore the negative answer. \r
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\n" ); document.write( "\n" ); document.write( "So the only solution is x = 7\r
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\n" ); document.write( "\n" ); document.write( "This means that Blanche is 7 years old currently.
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