document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=725564>Question 725564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present age of a girl is two fifth the age of her father.Express the above statement as a linear equation in two varible. Also answer the following questions:-<BR>\n" );
document.write( "a. The age of the girl when father is 40 years.<BR>\n" );
document.write( "B. The age of father when the girl is 22 years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444200 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'g' be the present age of the girl and 'f' be the age of the father.\r<BR>\n" );
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document.write( "Therefore, g = (2/5)f or<BR>\n" );
document.write( "5g - 2f = 0 is the required equation\r<BR>\n" );
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document.write( "a. When f = 40\r<BR>\n" );
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document.write( "g = (2/5)*40 = 16 years\r<BR>\n" );
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document.write( "b.When g = 22\r<BR>\n" );
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document.write( "f = (5/2)*22 = 55 years\r<BR>\n" );
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document.write( " </SPAN>\n" );
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