document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=725565>Question 725565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the age of two friends A&B differs by 3 yrs.A's father D is twice as old as A and B is twice as old as sister C. the ages of C & D differ by 30 yrs. Find their ages of A & B?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444199 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:\r<BR>\n" );
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document.write( "Given : A - B = 3 ------------eq.1<BR>\n" );
document.write( "        D = 2A    ------------eq.2<BR>\n" );
document.write( "        B = 2C or C = B/2 ----eq.3<BR>\n" );
document.write( "        D - C = 30 -----------eq.4\r<BR>\n" );
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document.write( "Put eq.2 , eq.3 in eq.4, we get\r<BR>\n" );
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document.write( "2A - B/2 = 30\r<BR>\n" );
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document.write( "4A - B = 60 ------------------eq.5\r<BR>\n" );
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document.write( "Solving eq.1 and 5, we get,\r<BR>\n" );
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document.write( "A = 19<BR>\n" );
document.write( "B = 16 </SPAN>\n" );
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