document.write( "Question 63692: Please solve the following problem using the a)Arithmetic method and proportional relationship method.
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document.write( "1. In mixing fuel for a 4 cycle motor, one must mix 4 parts of oil with 16 parts gasoline. How much oil is needed to mix with 24 liters of gasoline. \n" );
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Algebra.Com's Answer #44419 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! oil/gas=4/16 or 1/4 so to get 24 liters of mix you need 4 times as much gas as oil. \n" ); document.write( "o+4o=24 \n" ); document.write( "5o=24 \n" ); document.write( "o=24/5 \n" ); document.write( "o=4.8 liters of oil mixed with \n" ); document.write( "4*4.8=19.2 liters of gas to give you 24 liters of a 1/4 mix p \n" ); document.write( "proof \n" ); document.write( "4.8+19.2=24 \n" ); document.write( "24=24 & \n" ); document.write( "4.8/19.2=1/4 cross multiplying we get \n" ); document.write( "19.2=19.2 \n" ); document.write( " \n" ); document.write( " |