document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63718>Question 63718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely:\r<BR>\n" );
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document.write( "2ax^2 - 6ax -2a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44415 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2AX^2-6AX-2A<BR>\n" );
document.write( "2A(X^2-3X-1) USING THE QUADRATIC EQUATION WE GET<BR>\n" );
document.write( "X=(-B+-SQRT[B^2-4AC])/2A<BR>\n" );
document.write( "X=(3+-SQRT[9-4*1*-1])/281<BR>\n" );
document.write( "X=(3+-SQRT[9+4])/2<BR>\n" );
document.write( "X=(3+-SQRT13])/2<BR>\n" );
document.write( "X=(3+-3.6)/2<BR>\n" );
document.write( "X=(3+3.6)/2<BR>\n" );
document.write( "X=6.6/2<BR>\n" );
document.write( "X=3.3 SOLUTION<BR>\n" );
document.write( "X=(3-3.6)/2<BR>\n" );
document.write( "X=-.6/2<BR>\n" );
document.write( "X=-.3 SOLUTION THUS WE HAVE THE TWOO FACTORS OF (X^2-3X-1) <BR>\n" );
document.write( "2A(X-3.3)(X+.3) </SPAN>\n" );
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