document.write( "Question 63714: Jonathan has $7.00 in nickels, dimes, and quarters. He has twice as many dimes as nickels, and 3 times as many quarters as nickels. He has 42 coins altogether. How many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #44410 by checkley71(8403)\"\" \"About 
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N+D+Q=42 GIVEN
\n" ); document.write( "700=5N+10D+25Q GIVEN
\n" ); document.write( "D=2N
\n" ); document.write( "Q=3N NOW WE SUBSTITUTE THESE BVALUES INTO EITHER EQUATION & WE GET
\n" ); document.write( "N+2N+3N=42
\n" ); document.write( "6N=42
\n" ); document.write( "N=42/6
\n" ); document.write( "N=7 NUMBER OF NICKELS
\n" ); document.write( "D=2*7
\n" ); document.write( "D=14 NUMBER OF DIMES
\n" ); document.write( "Q=3*7
\n" ); document.write( "Q=21 NUMBER OF QUARTERS
\n" ); document.write( "PROOF
\n" ); document.write( "700=5*7+10*14+25*21
\n" ); document.write( "700=35+140+525
\n" ); document.write( "700=700
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