document.write( "Question 63714: Jonathan has $7.00 in nickels, dimes, and quarters. He has twice as many dimes as nickels, and 3 times as many quarters as nickels. He has 42 coins altogether. How many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #44410 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! N+D+Q=42 GIVEN \n" ); document.write( "700=5N+10D+25Q GIVEN \n" ); document.write( "D=2N \n" ); document.write( "Q=3N NOW WE SUBSTITUTE THESE BVALUES INTO EITHER EQUATION & WE GET \n" ); document.write( "N+2N+3N=42 \n" ); document.write( "6N=42 \n" ); document.write( "N=42/6 \n" ); document.write( "N=7 NUMBER OF NICKELS \n" ); document.write( "D=2*7 \n" ); document.write( "D=14 NUMBER OF DIMES \n" ); document.write( "Q=3*7 \n" ); document.write( "Q=21 NUMBER OF QUARTERS \n" ); document.write( "PROOF \n" ); document.write( "700=5*7+10*14+25*21 \n" ); document.write( "700=35+140+525 \n" ); document.write( "700=700 \n" ); document.write( " \n" ); document.write( " |