document.write( "Question 725285: The length of a rectangular piece of carpet is 5 meters less than twice its width. Find the dimensions of the carpet if the area is 33 square meters. \n" ); document.write( "
Algebra.Com's Answer #444095 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! AREA=LW \n" ); document.write( "L=2W-5 \n" ); document.write( "33=(2W-5)W \n" ); document.write( "33=2W^2-5W \n" ); document.write( "2W^2-5W+33=0 \n" ); document.write( "(2W-11)(W+3)=0 \n" ); document.write( "2W-11=0 \n" ); document.write( "2W=11 \n" ); document.write( "W=11/2 \n" ); document.write( "W=5.5 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*5.5-5 \n" ); document.write( "L=11-5 \n" ); document.write( "L=6 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "33=6*5.5 \n" ); document.write( "33=33\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |