document.write( "Question 725322: 6x^2+18x-600
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Algebra.Com's Answer #444094 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2B18x-600\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"6%28x%5E2%2B3x-100%29\" Factor out the GCF \"6\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"x%5E2%2B3x-100\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2%2B3x-100\", we can see that the first coefficient is \"1\", the second coefficient is \"3\", and the last term is \"-100\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"-100\" to get \"%281%29%28-100%29=-100\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-100\" (the previous product) and add to the second coefficient \"3\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-100\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-100\":\r
\n" ); document.write( "\n" ); document.write( "1,2,4,5,10,20,25,50,100\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-5,-10,-20,-25,-50,-100\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-100\".\r
\n" ); document.write( "\n" ); document.write( "1*(-100) = -100
\n" ); document.write( "2*(-50) = -100
\n" ); document.write( "4*(-25) = -100
\n" ); document.write( "5*(-20) = -100
\n" ); document.write( "10*(-10) = -100
\n" ); document.write( "(-1)*(100) = -100
\n" ); document.write( "(-2)*(50) = -100
\n" ); document.write( "(-4)*(25) = -100
\n" ); document.write( "(-5)*(20) = -100
\n" ); document.write( "(-10)*(10) = -100\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"3\":\r
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First NumberSecond NumberSum
1-1001+(-100)=-99
2-502+(-50)=-48
4-254+(-25)=-21
5-205+(-20)=-15
10-1010+(-10)=0
-1100-1+100=99
-250-2+50=48
-425-4+25=21
-520-5+20=15
-1010-10+10=0
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that there are no pairs of numbers which add to \"3\". So \"x%5E2%2B3x-100\" cannot be factored.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2%2B18x-600\" simply factors to \"6%28x%5E2%2B3x-100%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"6x%5E2%2B18x-600=6%28x%5E2%2B3x-100%29\".
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